Integrand size = 21, antiderivative size = 164 \[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=-\frac {3 i b e (a+b \arctan (c+d x))^2}{2 d}-\frac {3 b e (c+d x) (a+b \arctan (c+d x))^2}{2 d}+\frac {e (a+b \arctan (c+d x))^3}{2 d}+\frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}-\frac {3 b^2 e (a+b \arctan (c+d x)) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}-\frac {3 i b^3 e \operatorname {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{2 d} \]
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Time = 0.17 (sec) , antiderivative size = 164, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.476, Rules used = {5151, 12, 4946, 5036, 4930, 5040, 4964, 2449, 2352, 5004} \[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=-\frac {3 b^2 e \log \left (\frac {2}{1+i (c+d x)}\right ) (a+b \arctan (c+d x))}{d}-\frac {3 i b e (a+b \arctan (c+d x))^2}{2 d}-\frac {3 b e (c+d x) (a+b \arctan (c+d x))^2}{2 d}+\frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}+\frac {e (a+b \arctan (c+d x))^3}{2 d}-\frac {3 i b^3 e \operatorname {PolyLog}\left (2,1-\frac {2}{i (c+d x)+1}\right )}{2 d} \]
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Rule 12
Rule 2352
Rule 2449
Rule 4930
Rule 4946
Rule 4964
Rule 5004
Rule 5036
Rule 5040
Rule 5151
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int e x (a+b \arctan (x))^3 \, dx,x,c+d x\right )}{d} \\ & = \frac {e \text {Subst}\left (\int x (a+b \arctan (x))^3 \, dx,x,c+d x\right )}{d} \\ & = \frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}-\frac {(3 b e) \text {Subst}\left (\int \frac {x^2 (a+b \arctan (x))^2}{1+x^2} \, dx,x,c+d x\right )}{2 d} \\ & = \frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}-\frac {(3 b e) \text {Subst}\left (\int (a+b \arctan (x))^2 \, dx,x,c+d x\right )}{2 d}+\frac {(3 b e) \text {Subst}\left (\int \frac {(a+b \arctan (x))^2}{1+x^2} \, dx,x,c+d x\right )}{2 d} \\ & = -\frac {3 b e (c+d x) (a+b \arctan (c+d x))^2}{2 d}+\frac {e (a+b \arctan (c+d x))^3}{2 d}+\frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}+\frac {\left (3 b^2 e\right ) \text {Subst}\left (\int \frac {x (a+b \arctan (x))}{1+x^2} \, dx,x,c+d x\right )}{d} \\ & = -\frac {3 i b e (a+b \arctan (c+d x))^2}{2 d}-\frac {3 b e (c+d x) (a+b \arctan (c+d x))^2}{2 d}+\frac {e (a+b \arctan (c+d x))^3}{2 d}+\frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}-\frac {\left (3 b^2 e\right ) \text {Subst}\left (\int \frac {a+b \arctan (x)}{i-x} \, dx,x,c+d x\right )}{d} \\ & = -\frac {3 i b e (a+b \arctan (c+d x))^2}{2 d}-\frac {3 b e (c+d x) (a+b \arctan (c+d x))^2}{2 d}+\frac {e (a+b \arctan (c+d x))^3}{2 d}+\frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}-\frac {3 b^2 e (a+b \arctan (c+d x)) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}+\frac {\left (3 b^3 e\right ) \text {Subst}\left (\int \frac {\log \left (\frac {2}{1+i x}\right )}{1+x^2} \, dx,x,c+d x\right )}{d} \\ & = -\frac {3 i b e (a+b \arctan (c+d x))^2}{2 d}-\frac {3 b e (c+d x) (a+b \arctan (c+d x))^2}{2 d}+\frac {e (a+b \arctan (c+d x))^3}{2 d}+\frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}-\frac {3 b^2 e (a+b \arctan (c+d x)) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}-\frac {\left (3 i b^3 e\right ) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+i (c+d x)}\right )}{d} \\ & = -\frac {3 i b e (a+b \arctan (c+d x))^2}{2 d}-\frac {3 b e (c+d x) (a+b \arctan (c+d x))^2}{2 d}+\frac {e (a+b \arctan (c+d x))^3}{2 d}+\frac {e (c+d x)^2 (a+b \arctan (c+d x))^3}{2 d}-\frac {3 b^2 e (a+b \arctan (c+d x)) \log \left (\frac {2}{1+i (c+d x)}\right )}{d}-\frac {3 i b^3 e \operatorname {PolyLog}\left (2,1-\frac {2}{1+i (c+d x)}\right )}{2 d} \\ \end{align*}
Time = 0.29 (sec) , antiderivative size = 196, normalized size of antiderivative = 1.20 \[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=\frac {e \left (3 b^2 (-i+c+d x) (-b+a (i+c+d x)) \arctan (c+d x)^2+b^3 \left (1+c^2+2 c d x+d^2 x^2\right ) \arctan (c+d x)^3+3 b \arctan (c+d x) \left (a \left (-2 b (c+d x)+a \left (1+c^2+2 c d x+d^2 x^2\right )\right )-2 b^2 \log \left (1+e^{2 i \arctan (c+d x)}\right )\right )+a \left (a (c+d x) (-3 b+a c+a d x)-6 b^2 \log \left (\frac {1}{\sqrt {1+(c+d x)^2}}\right )\right )+3 i b^3 \operatorname {PolyLog}\left (2,-e^{2 i \arctan (c+d x)}\right )\right )}{2 d} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 320 vs. \(2 (150 ) = 300\).
Time = 0.55 (sec) , antiderivative size = 321, normalized size of antiderivative = 1.96
method | result | size |
derivativedivides | \(\frac {\frac {e \,a^{3} \left (d x +c \right )^{2}}{2}+e \,b^{3} \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )^{3}}{2}+\frac {\arctan \left (d x +c \right )^{3}}{2}-\frac {3 \left (d x +c \right ) \arctan \left (d x +c \right )^{2}}{2}+\frac {3 \arctan \left (d x +c \right ) \ln \left (1+\left (d x +c \right )^{2}\right )}{2}+\frac {3 i \left (\ln \left (d x +c -i\right ) \ln \left (1+\left (d x +c \right )^{2}\right )-\frac {\ln \left (d x +c -i\right )^{2}}{2}-\operatorname {dilog}\left (-\frac {i \left (d x +c +i\right )}{2}\right )-\ln \left (d x +c -i\right ) \ln \left (-\frac {i \left (d x +c +i\right )}{2}\right )\right )}{4}-\frac {3 i \left (\ln \left (d x +c +i\right ) \ln \left (1+\left (d x +c \right )^{2}\right )-\frac {\ln \left (d x +c +i\right )^{2}}{2}-\operatorname {dilog}\left (\frac {i \left (d x +c -i\right )}{2}\right )-\ln \left (d x +c +i\right ) \ln \left (\frac {i \left (d x +c -i\right )}{2}\right )\right )}{4}\right )+3 e a \,b^{2} \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )^{2}}{2}+\frac {\arctan \left (d x +c \right )^{2}}{2}-\left (d x +c \right ) \arctan \left (d x +c \right )+\frac {\ln \left (1+\left (d x +c \right )^{2}\right )}{2}\right )+3 e \,a^{2} b \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )}{2}-\frac {d x}{2}-\frac {c}{2}+\frac {\arctan \left (d x +c \right )}{2}\right )}{d}\) | \(321\) |
default | \(\frac {\frac {e \,a^{3} \left (d x +c \right )^{2}}{2}+e \,b^{3} \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )^{3}}{2}+\frac {\arctan \left (d x +c \right )^{3}}{2}-\frac {3 \left (d x +c \right ) \arctan \left (d x +c \right )^{2}}{2}+\frac {3 \arctan \left (d x +c \right ) \ln \left (1+\left (d x +c \right )^{2}\right )}{2}+\frac {3 i \left (\ln \left (d x +c -i\right ) \ln \left (1+\left (d x +c \right )^{2}\right )-\frac {\ln \left (d x +c -i\right )^{2}}{2}-\operatorname {dilog}\left (-\frac {i \left (d x +c +i\right )}{2}\right )-\ln \left (d x +c -i\right ) \ln \left (-\frac {i \left (d x +c +i\right )}{2}\right )\right )}{4}-\frac {3 i \left (\ln \left (d x +c +i\right ) \ln \left (1+\left (d x +c \right )^{2}\right )-\frac {\ln \left (d x +c +i\right )^{2}}{2}-\operatorname {dilog}\left (\frac {i \left (d x +c -i\right )}{2}\right )-\ln \left (d x +c +i\right ) \ln \left (\frac {i \left (d x +c -i\right )}{2}\right )\right )}{4}\right )+3 e a \,b^{2} \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )^{2}}{2}+\frac {\arctan \left (d x +c \right )^{2}}{2}-\left (d x +c \right ) \arctan \left (d x +c \right )+\frac {\ln \left (1+\left (d x +c \right )^{2}\right )}{2}\right )+3 e \,a^{2} b \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )}{2}-\frac {d x}{2}-\frac {c}{2}+\frac {\arctan \left (d x +c \right )}{2}\right )}{d}\) | \(321\) |
parts | \(e \,a^{3} \left (\frac {1}{2} d \,x^{2}+c x \right )+\frac {e \,b^{3} \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )^{3}}{2}+\frac {\arctan \left (d x +c \right )^{3}}{2}-\frac {3 \left (d x +c \right ) \arctan \left (d x +c \right )^{2}}{2}+\frac {3 \arctan \left (d x +c \right ) \ln \left (1+\left (d x +c \right )^{2}\right )}{2}+\frac {3 i \left (\ln \left (d x +c -i\right ) \ln \left (1+\left (d x +c \right )^{2}\right )-\frac {\ln \left (d x +c -i\right )^{2}}{2}-\operatorname {dilog}\left (-\frac {i \left (d x +c +i\right )}{2}\right )-\ln \left (d x +c -i\right ) \ln \left (-\frac {i \left (d x +c +i\right )}{2}\right )\right )}{4}-\frac {3 i \left (\ln \left (d x +c +i\right ) \ln \left (1+\left (d x +c \right )^{2}\right )-\frac {\ln \left (d x +c +i\right )^{2}}{2}-\operatorname {dilog}\left (\frac {i \left (d x +c -i\right )}{2}\right )-\ln \left (d x +c +i\right ) \ln \left (\frac {i \left (d x +c -i\right )}{2}\right )\right )}{4}\right )}{d}+\frac {3 e a \,b^{2} \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )^{2}}{2}+\frac {\arctan \left (d x +c \right )^{2}}{2}-\left (d x +c \right ) \arctan \left (d x +c \right )+\frac {\ln \left (1+\left (d x +c \right )^{2}\right )}{2}\right )}{d}+\frac {3 e \,a^{2} b \left (\frac {\left (d x +c \right )^{2} \arctan \left (d x +c \right )}{2}-\frac {d x}{2}-\frac {c}{2}+\frac {\arctan \left (d x +c \right )}{2}\right )}{d}\) | \(328\) |
risch | \(\text {Expression too large to display}\) | \(1413\) |
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\[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=\int { {\left (d e x + c e\right )} {\left (b \arctan \left (d x + c\right ) + a\right )}^{3} \,d x } \]
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\[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=e \left (\int a^{3} c\, dx + \int a^{3} d x\, dx + \int b^{3} c \operatorname {atan}^{3}{\left (c + d x \right )}\, dx + \int 3 a b^{2} c \operatorname {atan}^{2}{\left (c + d x \right )}\, dx + \int 3 a^{2} b c \operatorname {atan}{\left (c + d x \right )}\, dx + \int b^{3} d x \operatorname {atan}^{3}{\left (c + d x \right )}\, dx + \int 3 a b^{2} d x \operatorname {atan}^{2}{\left (c + d x \right )}\, dx + \int 3 a^{2} b d x \operatorname {atan}{\left (c + d x \right )}\, dx\right ) \]
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\[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=\int { {\left (d e x + c e\right )} {\left (b \arctan \left (d x + c\right ) + a\right )}^{3} \,d x } \]
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\[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=\int { {\left (d e x + c e\right )} {\left (b \arctan \left (d x + c\right ) + a\right )}^{3} \,d x } \]
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Timed out. \[ \int (c e+d e x) (a+b \arctan (c+d x))^3 \, dx=\int \left (c\,e+d\,e\,x\right )\,{\left (a+b\,\mathrm {atan}\left (c+d\,x\right )\right )}^3 \,d x \]
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